SOLUTION: Becky and Delia, living 450 meters apart, leave their homes on a pedicab and travel toward each other. If Becky averages 3 meters per minute more than Delia and they meet after 30

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Question 1133384: Becky and Delia, living 450 meters apart, leave their homes on a pedicab and travel toward each other. If Becky averages 3 meters per minute more than Delia and they meet after 30 minutes, then find their rates of cycling.


Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x m/min for slower
x+3 m/minfor faster
30 minutes for 450 meters is 15 meters/min
combined speed is 2x+3 m/min
2x+3=15
2x=12
x=6 m/min for Delia
x+3=9 m/min for Becky

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +v+ = the speed of the slower bike in m/min
+v+%2B+3+ = the speed of the faster bike in m/min
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Since their speed will add, you can view this as
one of them moving at the sum of their speeds
and the other one standing still, so I can say:
+450+=+%28+v+%2B+v+%2B+3+%29%2A30+
+450+=+%28+2v+%2B+3+%29%2A30+
+450+=+60v+%2B+90+
+60v+=+360+
+v+=+6+ m/min
and
+v+%2B+3+=+9+ m/min
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Their speeds are 6 m/min and 9 m/min
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check:
+d%5B1%5D+=6%2A30+
+d%5B1%5D+=+180+
and
+d%5B2%5D+=+9%2A30+
+d%5B2%5D+=+270+
and
+d%5B1%5D+%2B+d%5B2%5D+=+180+%2B+270+
+d%5B1%5D+%2B+d%5B2%5D+=+450+ m
OK