SOLUTION: Prove that the area of the minor segment cut off from a circle of radius r cm by a chord c cm from the centre of the circle is given by
(1/2)[2π{cos^(-1)(c/r)}*r²/180° - 2c(r
Algebra ->
Test
-> SOLUTION: Prove that the area of the minor segment cut off from a circle of radius r cm by a chord c cm from the centre of the circle is given by
(1/2)[2π{cos^(-1)(c/r)}*r²/180° - 2c(r
Log On
Question 1131926: Prove that the area of the minor segment cut off from a circle of radius r cm by a chord c cm from the centre of the circle is given by
(1/2)[2π{cos^(-1)(c/r)}*r²/180° - 2c(r²-c²)^½]
That's equivalent to what you have above since
and the inverse cosine is multiplied by
to change degrees to radians, for apparently degrees are assumed
by the author of this problem. If radians were assumed for the
inverse cosine, we would not use the factor .
Edwin
