SOLUTION: A husband is 3years older than his wife. the sum of their ages is 73 years.calculate the difference between the square of their ages

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Question 1117447: A husband is 3years older than his wife. the sum of their ages is 73 years.calculate the difference between the square of their ages

Found 2 solutions by Alan3354, math_helper:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
H - W = 3
H + W = 73
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Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
h - w = 3
h + w = 73
The difference between the square of their ages +h%5E2+-+w%5E2+ is (h-w)(h+w) = 3*73 = +highlight%28219%29+
(yrs^2 units).