SOLUTION: The equation of the locus of a point which is always equidistant from the point (a+b,a-b) and (a-b,a+b) is

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Question 1058693: The equation of the locus of a point which is always equidistant from the point (a+b,a-b) and (a-b,a+b) is
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
The equation of the locus of highlight%28cross%28a_point_which_is_always%29%29 points that are equidistant from the highlight%28cross%28point%29%29 points (a+b,a-b) and (a-b,a+b) is
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x = y.

And ignore the writing by "josgarithmetic": it is not relevant.


Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope and the midpoint of those two points.

The points equidistant from those two variable described points would be a LINE. This line will intersect the midpoint of the two described points and will have slope negative reciprocal of that of the two described points. Now, this is why "find slope and midpoint of those...".