SOLUTION: please help me out my problem is: If a+2b=9 and ab=7 than what is the value of aČ+4b?

Algebra ->  Test -> SOLUTION: please help me out my problem is: If a+2b=9 and ab=7 than what is the value of aČ+4b?       Log On


   



Question 1022705: please help me out my problem is:
If a+2b=9 and ab=7 than what is the value of aČ+4b?

Found 2 solutions by Edwin McCravy, Theo:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Solve a+2b = 9 for a, get a = 9-2b

Square both sides of 

a+2b = 9

Substitute ab=7 for ab, and (9-2b) for a

Simplify, get 0 on the right side.

You get a quadratic equation in b that you 
can divide thru by 4.

Simplify

The quadratic equation is factorable

You get 2 solutions for b

Substitute each in a = 9-2b to find two solutions for a

Substitute the values of a and b in

aČ+4b, and get 2 solutions.

Edwin

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
If a + 2b = 9 and ab = 7 than what is the value of a^2 + 4b?

you have a + 2b = 9 and you have ab = 7.

solve for a in ab = 7 to get a = 7/b.

a + 2b = 9 becomes 7/b + 2b = 9 after you replace a with 7/b.

your equation to solve is now 7/b + 2b = 9.

multiply both sides of that equation by b to get 7 + 2b^2 = 9b.

subtract 9b from both sides of the equation and reorder the terms in descending order to get 2b^2 - 9b + 7 = 0

factor that quadratic to get (2b-7) * (b-1) = 0

solve for b to get b = 7/2 or b = 1.

when b = 7/2, a + 2b = 9 becomes a + 7 = 9 which becomes a = 2.

when b = 1, a + 2b = 9 becomes a + 2 = 9 which becomes a = 7.

you have two possibilities.

a = 2 and b = 7/2.

a = 7 and b = 1.

when a = 2 and b = 7/2, a + 2b = 9 becomes 2 + 7 = 9 which becomes 9 = 9 which is true.

when a = 2 and b = 7/2 ab = 7 becomes 2 * 7/2 = 7 which becomes 7 = 7 which is true.

when a = 7 and b = 1, a + 2b = 9 becomes 7 + 2 = 9 which becomes 9 = 9 which is true.

when a = 7 and b = 1, ab = 7 becomes 7 * 1 = 7 which becomes 7 = 7 which is true.

the above 4 equations confirm the solutions are correct so far.

so we have two pairs of solutions in the form of (a,b).

the are (2,7/2) and (7,1).

now we look at a^2 + 4b.

when a = 2 and b = 7/2, a^2 + 4b = 4 + 14 = 18.

when a = 7 and b = 1, a^2 + 4b = 49 + 4 = 53.

you have 2 solutions.

a^2 + 4b = 18 when a = 2 and b = 7/2.

a^2 + 4b = 53 when a = 7 and b = 1.