SOLUTION: There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The pr
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-> SOLUTION: There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The pr
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Question 970604: There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The probability that Mr. X if selected would introduce computer education in the college is 0.3. The probabilities of Mr. Y and Mr. Z doing the same are 0.5 and 0.8 respectively. What is the
probability that there was computer education in the college?
You can put this solution on YOUR website! There were three candidates for the position of the chairman of a college Mr. X, Mr. Y and Mr. Z whose chances of getting appointments are in
the ratio 4:2:3 respectively. The probability that Mr. X if selected would introduce computer education in the college is 0.3. The probabilities of Mr. Y and Mr. Z doing the same are 0.5 and 0.8 respectively. What is the
probability that there was computer education in the college?
Solution:
First we compute the probability that there was NO computer education in the college.
P(C') = =
Therefore, the probability that there was computer education in the college is
P(C) = 1 - P(C') = 1 - 22/45 =
