SOLUTION: The Great Pyramid of King Khufu was built of limestone in Egypt over a 20-year time period from 2580 bc to 2560 bc. Its base is a square with side length 230 m and its height

Algebra ->  Statistics  -> Normal-probability -> SOLUTION: The Great Pyramid of King Khufu was built of limestone in Egypt over a 20-year time period from 2580 bc to 2560 bc. Its base is a square with side length 230 m and its height       Log On


   



Question 1202499: The Great Pyramid of King Khufu was built of limestone in
Egypt over a 20-year time period from 2580 bc to 2560 bc.
Its base is a square with side length 230 m and its height
when built was 147 m. (It was the tallest man-made structure
in the world for more than 3800 years.) The density of
the limestone is about 2400 kg/m3
(a) Estimate the total work done in building the pyramid.
(b) If each laborer worked 10 hours a day for 20 years, for
340 days a year, and did 250 J/h of work in lifting the
limestone blocks into place, about how many laborers
were needed to construct the pyramid?

Answer by ikleyn(52786) About Me  (Show Source):
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The Great Pyramid of King Khufu was built of limestone in Egypt over a 20-year time period
from 2580 bc to 2560 bc.
Its base is a square with side length 230 m and its height when built was 147 m.
(It was the tallest man-made structure in the world for more than 3800 years.)
The density of the limestone is about 2400 kg/m3
(a) Estimate the total work done in building the pyramid.
(b) If each laborer worked 10 hours a day for 20 years, for 340 days a year,
and did 250 J/h of work in lifting the limestone blocks into place,
about how many laborers were needed to construct the pyramid?
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(a)  To answer question (a), find the volume of the pyramid

         V = %281%2F3%29%2Aa%5E2%2Ah = %281%2F3%29%2A230%5E2%2A170 = 2,997,666.667 m^3.


     Then multiply the volume by the density to get the mass of the material

         M = V*d = 2997666.667*2400 = 7,194,400,001 kilograms.


     Then multiply the mass by the gravity acceleration g= 9.81 m/s^2 and by one fourth of the height 
     to get the work done (the center of the gravity of a pyramid is at 1/4 of the height)

         W = M%2Ag%2A%281%2F4%29%2AH = 7194400001%2A9.81%2A%281%2F4%29%2A170 = 2.99953E+12 joules.    (1)


     It is the  ANSWER  to question (a).



(b)  The work done by one laborer per "year" is

         w = 340*10*250 = 850000 joules per laborer per year.    (2)


     To answer question (b), divide the number W = 2.99953E+12 joules of (1) by 20w,
     where w is the number w= 850000 of (2).  You will get

         the number of laborer = 2.99953E+12 : (20*850000) = 176,443  (rounded).


    It is the  ANSWER  to question (b).

Solved.

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To read more about this construction. read this Wikipedia article
https://en.wikipedia.org/wiki/Great_Pyramid_of_Giza