SOLUTION: A class consisting of 8 men and 7 women we're 2 selected randomly to represent the class in a dabate find the probability that the 2 selected are (I) both men (ii) both woman (iii

Algebra ->  Statistics  -> Normal-probability -> SOLUTION: A class consisting of 8 men and 7 women we're 2 selected randomly to represent the class in a dabate find the probability that the 2 selected are (I) both men (ii) both woman (iii      Log On


   

Question 1201898: A class consisting of 8 men and 7 women we're 2 selected randomly to represent the class in a dabate find the probability that the 2 selected are (I) both men (ii) both woman (iii) of the same Sex (iv) of the different Sex.
Answer by ikleyn(52785) About Me  (Show Source):
You can put this solution on YOUR website!
.
A class consisting of 8 men and 7 women we're 2 selected randomly to represent the class in a dabate
find the probability that the 2 selected are
(a) both men
(b) both woman
(c) of the same Sex
(d) of the different Sex.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


        I will not edit your post - it really bothered me to edit every post.
        I will keep your text as is, although it really needs to be edited. 


Total people is  8+7 = 15.


(a)  both men        P(both men)   = %288%2F15%29%2A%287%2F14%29 = 56%2F210 = 4%2F15.


(b)  both women      P(both women) = %287%2F15%29%2A%286%2F14%29 = 42%2F210 = 3%2F15.


(c)  of the same sex P(both men)  +  P(both women) = 4%2F15 + 3%2F15 = 7%2F15.


(d)  of the different sex: the complement to the value of (c)  1 - 7%2F15 = 8%2F15.

Solved.

-------------

The formulas are  SELF-EXPLANATORY  and intuitively clear.