SOLUTION: Average Score = 88 Standard Deviation = 5 *Assuming that the scores were normally distributed: Number of students who took test = 1250 --what percentage of students would have

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Question 1168630: Average Score = 88
Standard Deviation = 5
*Assuming that the scores were normally distributed:
Number of students who took test = 1250
--what percentage of students would have a score less than 80?
a. What is the z-score?
b. What is percentage?
MY ANSWER:
a.-1.60
b. 05.48 %
-hi can you check my answer if it is correct?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct.
z=(x-mean)/sd