SOLUTION: Harold phone 36 apps, 4/9 of which are games. He downloads more games( and no other apps) so that 2/3 of the apps on his phone are now now games. How many games did he download?

Algebra ->  Statistics  -> Normal-probability -> SOLUTION: Harold phone 36 apps, 4/9 of which are games. He downloads more games( and no other apps) so that 2/3 of the apps on his phone are now now games. How many games did he download?       Log On


   



Question 1141630: Harold phone 36 apps, 4/9 of which are games. He downloads more games( and no other apps) so that 2/3 of the apps on his phone are now now games. How many games did he download?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
1)  4%2F9 of 36 apps is  16 apps.

    So, Harold had 16 games in his phone initially.



2)  The new proportion is  


        %2816%2Bx%29%2F%2836%2Bx%29 = 2%2F3,


    which implies  


        3*(16+x) = 2*(36+x)

        48 + 3x = 72 + 2x


        3x - 2x = 72 - 48

         x      = 24.


ANSWER.  Hi downloaded 24 games.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


4/9 of 36 is 16; so he originally had 16 games and 20 other apps.

He adds more games and no other apps, after which 2/3 of the apps are games. So

%2816%2Bx%29%2F%2836%2Bx%29+=+2%2F3

Solve using basic algebra....

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Or try solving using logical reasoning instead of formal algebra; something like this:

There are 20 apps on his phone that are not games. After he adds the additional game apps, those 20 other apps are now 1/3 of the total (because 2/3 are now games).

1/3 of the total being 20 apps means the total number of apps is now 3*20 = 60. And since he originally had a total of 36 apps, the number of game apps he added was 60-36 = 24.