SOLUTION: In a program designed to help patients stop​ smoking,
195
195 patients were given sustained​ care, and
83.6
83.6​% of them were no longer smoking after one
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-> SOLUTION: In a program designed to help patients stop​ smoking,
195
195 patients were given sustained​ care, and
83.6
83.6​% of them were no longer smoking after one
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Question 1129604: In a program designed to help patients stop smoking,
195
195 patients were given sustained care, and
83.6
83.6% of them were no longer smoking after one month. Use a
0.01
0.01 significance level to test the claim that
80
80% of patients stop smoking when given sustained care. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Assuming random sample, etc., this is a one sample proportion test
Ho: 80% stop
Ha: some other number stop
test statistic is a z and critical value is |z|>2.576
z=(p hat-p)/sqrt((p*(1-p)/n)' sqrt term is sqrt(.8*.2/195)=0.0286
z=0.036/0.0286=1.26
Fail to reject Ho; insufficient evidence to reject Ho
