SOLUTION: My younger brother had a run in earlier with Médecins Sans Frontières. He narrowly escaped from an adverse verdict by the court........ What he wants is that he be left alone to

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Question 1057876: My younger brother had a run in earlier with Médecins Sans Frontières. He narrowly escaped from an adverse verdict by the court........ What he wants is that he be left alone to run his small café......
He asked my oldest brother if he can conduct a survey for him about justice in the Canadian Court.
An initial survey was performed right after Médecins Sans Frontières accused my brother of wrong doing. Of 1852 customers, 53 were against the aggressive tactics of Médecins Sans Frontières. After my brother was cleared by the court, a follow-up survey was performed. Of 4699 customers, 1751 said they did not agree with the aggressive tactics of Médecins Sans Frontières.

My question below please show work
At the 1% significance level, do the data suggest that a higher percentage of customers were against Médecins Sans Frontières after the court case?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An initial survey was performed right after Médecins Sans Frontières accused my brother of wrong doing. Of 1852 customers, 53 were against the aggressive tactics of Médecins Sans Frontières. After my brother was cleared by the court, a follow-up survey was performed. Of 4699 customers, 1751 said they did not agree with the aggressive tactics of Médecins Sans Frontières.
My question below please show work
At the 1% significance level, do the data suggest that a higher percentage of customers were against Médecins Sans Frontières after the court case?
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Ho: p2 - p1 <= 0
Ha: p2 - p1 > 0 (higher percent were against)
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p2 = 1751/4699 = 0.373
p1 = 53/1852 = 0.029
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sample difference:: p2-p1 = 0.3436
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z(0.3436) = (0.3436-0)/sqrt[(0.373*0.6567/4699) + (0.029*0.971/1852)] = 41.87
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Note: That difference is 41 standard deviations above the mean.
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Conclusion:: That z-value is so high no p-value can be calculated.
That p-value is so small you could definitely reject Ho and conclude
that tke test results support Ha at the 1% significance level.
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Cheers,
Stan H.
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