Question 1056589: A golf instructor is interested in determining if her new technique for improving players’ golf scores is effective. She
takes four new students. She records their 18-hole scores before learning the technique and then after having taken her class.
She conducts a hypothesis test. The data are as follows.
Player 1 Player 2 Player 3 Player 4
Mean score before class 83 78 93 87
Mean score after class 80 80 86 86
Table 10.31
The correct decision is:
a. Reject H0.
b. Do not reject the H0.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Do not reject Ho
mean of the first is 85.25, and mean of second is 83
sd 1 is 6.34
sd 2 is 3.46
the two sample t is (mean1-mean2)/sqrt((s1^2/n1)+(s2^2/n2))
The df=6
n1 and n2 are 4 each
The critical value is 2.45 for t0.975, df=6
t=0.622, which does not exceed the critical value. (This is not surprising, given that the means are very similar and there are only 4 observations in each group).
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