SOLUTION: student receives test scores of 52, 83, and 91. The student final exam is 88 and homework score is 76. Each test is worth 20% the final exam is worth 25%, and the homework grade is

Algebra ->  Statistics  -> Describing-distributions-with-numbers -> SOLUTION: student receives test scores of 52, 83, and 91. The student final exam is 88 and homework score is 76. Each test is worth 20% the final exam is worth 25%, and the homework grade is      Log On


   



Question 1102088: student receives test scores of 52, 83, and 91. The student final exam is 88 and homework score is 76. Each test is worth 20% the final exam is worth 25%, and the homework grade is worth 15%. What is the students mean score in the class?
Mean:
Standard deviation:

Answer by Theo(13342) About Me  (Show Source):
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the procedure is shown in the following excel spreadsheet printout.

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in this particular case, the sum of frequency data is 1 because we are dealing with frequency data being a percent of the total.

the procedure still requires you to divide by the sum of the frequency data because you will not always be dealing with frequency as a percent of the total.

in that case, the sum of the frequency data will be something other than 1.

the following excel printout shows you the same data with frequency as a percent rather than as a decimal equivalent of percent.

the sum of frequency data is now 100 rather than 1.

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the following excel printout shows you the same data with frequency as 5 times the frequency as a percent rather than the frequency as a percent.

the sum of frequency data is now 500 rather than 100

$$$


in all cases, the weighted average and the weighted variance and the weighted standard deviation are all the same.