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Question 1036734: *How would you find the z-score and how would you consider it unusual or not? How would you find which percentile it would go in?
A certain brand of car has a mean and lifespan of 33,000 miles and a standard deviation of 2,150 miles.*
For 35,000 miles= .......
I know that I would do (35,000-33,000)/2,150 and that would give me .93 for my z-score and so on. I don't understand if it would be unusual or not and how it would fall into the percentile.
It gives me three other numbers like 30,850, 35,150 and 33,000 miles to place under the percentile. It gives an option of 16, 50 and 84 percentile but I thought you had used 68%, 95% and 99.7% if you are doing the Empirical Rule. Am I looking at it wrong?
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! A z-score of 0.93 tells you that your data is within 1 standard deviation from the mean
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Data beyond two standard deviations away from the mean is considered "unusual" data
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Also a z-score of 0.93 is 0.8238(from z-score table) which is 82.38%
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