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Question 1170271: The shoulder height for a random sample of six (6) fawns (deer less than 5 months old) in
a national park was , 𝑥 = 79.25 cm with population standard deviation 𝞂= 5.33 cm.
Compute an 80% confidence interval for the mean shoulder height of the population of
all fawns (deer less than 5 months old) in this national park. Analyze the result to
interpret its meaning
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! z=+/- 1.28
the half-interval is z*sigma/sqrt(n)
=1.28*5.33/sqrt(6)
=2.79
the interval is the mean +/- the half-interval
(76.54, 82.04) units cm
The calculator gives a slightly different result due to less rounding.
This means we do not know the true shoulder height of all the fawns in the park, but we are 80% confident that it is in the above interval.
That also means if we did 80 such 6 fawn samples, 80% of them would contain the true parameter, but we wouldn't know which ones.
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