SOLUTION: the area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of the rectangle. Round off your answer to the nearest

Algebra ->  Statistics  -> Central-limit-theorem -> SOLUTION: the area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of the rectangle. Round off your answer to the nearest       Log On


   

Question 1163435: the area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of the rectangle. Round off your answer to the nearest hundredth.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Let the width be x; then the length is 6x-4.

The area (length times width) is 20 square inches:

x%286x-4%29+=+20
6x%5E2-4x+=+20
6x%5E2-4x-20+=+0
3x%5E2-2x-5+=+0
%283x-5%29%28x%2B1%29+=+0

x+=+5%2F3 or x+=+-1

Obviously the negative solution makes no sense in the problem....

So x = 5/3; 6x-4 = 10-4 = 6; the area is 6(5/3) = 20.

ANSWER: The dimensions of the rectangle are 5/3 inches by 6 inches.

Convert the 5/3 to a decimal rounded to the nearest hundredth if you need to....