Question 1208046: A fair die is thrown once. Find the probability of obtaining :a six, an even number, a number greater than 3,a three or a five
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
A fair die is thrown once. Find the probability of obtaining:
(a) a six,
(b) an even number,
(c) a number greater than 3,
(d) a three or a five
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(a) P(a six) = P(a six of 6) = 1/6.
(b) P(an even number) = P(2 or 4 or 6 of 6) = 3/6 = 1/2.
(c) P(a number greater than 3) = P(4 or 5 or 6 of six) = 3/6 = 1/2.
(d) P(a three or a five) = P(3 or 5 of 6) = 2/6 = 1/3.
Solved.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The other tutor interpreted this as four different cases. It can also be interpreted as a single case.
"...a six, (or) an even number, (or) a number greater than 3, (or) a three or a five"
a six: only one number, 6
an even number: 2, 4 or 6
a number greater than 3: 4, 5, or 6
a three or a five: 3 or 5
All together: 2, 3, 4, 5, or 6
ANSWER: 5/6
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