SOLUTION: can someone help please? How to get the term containing p in the (3p- (2/p))^9 Thank you.

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Question 1095061: can someone help please?
How to get the term containing p in the (3p- (2/p))^9
Thank you.

Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!

The first term in the expansion will have the (3p) term to the 9th power.
The second term will have the (3p) term to the 8th power, and the (-2/p) term to the first power, resulting in a term with p to the 7th power.

Continuing that analysis we can see that the term in the expansion containing p to the first power must use the (3p) term 5 times and the (-2/p) term 4 times.

Then using binomial expansion, the term containing p in the expansion is
C%289%2C4%29%2A%283p%29%5E5%2A%28-2%2Fp%29%5E4
126%2A243p%5E5%2A%2816%2Fp%5E4%29
489888p