SOLUTION: 2 questions: if a= b+2, then (b-a)^4 = ? -16,-8,1, 8, 16 are the choices which of the following is the set of all real numbers x such that x + 3 > x + 5 empty set, set co

Algebra ->  Real-numbers -> SOLUTION: 2 questions: if a= b+2, then (b-a)^4 = ? -16,-8,1, 8, 16 are the choices which of the following is the set of all real numbers x such that x + 3 > x + 5 empty set, set co      Log On


   

Question 280655: 2 questions:
if a= b+2, then (b-a)^4 = ?
-16,-8,1, 8, 16 are the choices

which of the following is the set of all real numbers x such that x + 3 > x + 5
empty set, set containing all real number, set containing all negative real numbers, set containing all nonnegative real numbers or the set containing only zero
this is for an ACT practice sheet for a 10th grader in algebra II
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First take a=+b%2B2 and isolate b-a to get b-a=-2. Now raise both sides to the 4th power to get %28b-a%29%5E4=%28-2%29%5E4. I'll let you carry out the rest of the computations.

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If we subtract 'x' from both sides on x+%2B+3+%3E+x+%2B+5, we get 3%3E5 which is NEVER true for any value of 'x'. So there are NO solutions. This means that the solution set is the empty set. Recall that the empty set is the set with no elements.