SOLUTION: Each of three boxes has 10 balls with numbers from 0 to 9. You take out one ball from each box randomly. What is the probability that you have taken out
a. three “2”s?
b. 3 numbe
Algebra ->
Real-numbers
-> SOLUTION: Each of three boxes has 10 balls with numbers from 0 to 9. You take out one ball from each box randomly. What is the probability that you have taken out
a. three “2”s?
b. 3 numbe
Log On
Question 1120139: Each of three boxes has 10 balls with numbers from 0 to 9. You take out one ball from each box randomly. What is the probability that you have taken out
a. three “2”s?
b. 3 numbers that are the same? Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website!
a) (1/10)*(1/10)*(1/10) = = 0.001
b) (1/10)*(1/10) = = 0.01
Notice for part(b) that the first pick is x (where x=0,1,…9), so only the 2nd and 3rd picks need to match x. In contrast, part(a) stipulates that x=2 so we have a 1/10 probability of picking that particular x on pick #1.
An alternate way to view (b) vs (a): there are 10 possible picks where the 3 numbers match, and only one {2,2,2}, so the answer to (b) must be 10 times as great as (a).
