SOLUTION: 50 kg of tea, worth Rs 111, is made up of two sorts, part worth Rs 3 per kg and the rest worth Re 1.50 per kg. How much is there of each sort?

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: 50 kg of tea, worth Rs 111, is made up of two sorts, part worth Rs 3 per kg and the rest worth Re 1.50 per kg. How much is there of each sort?      Log On


   

Question 1062289: 50 kg of tea, worth Rs 111, is made up of two sorts, part worth Rs 3 per kg and the rest worth Re 1.50 per kg. How much is there of each sort?
Answer by josgarithmetic(39799) About Me  (Show Source):
You can put this solution on YOUR website!
VARIABLES
M=50     amount of tea mixture
T=111    cost of the mixture in Rs per kilogram
H=3      price of the more expensive tea
L=1.5    price of the cheaper tea
x        unknown amount of the cheaper tea
y        unknown amount of the higher priced tea


A starting system of equations for the description
system%28x%2By=M%2C%28Lx%2BHy%29%2FM=T%29
What you want to do is to solve for x and y.

A lesson on such a two-part mixture problem , https://www.algebra.com/my/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev