SOLUTION: ln e^-0.4

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Question 956758: ln e^-0.4
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
It helps to keep the language straight
+ln%28+e%5E%28-.4%29%29+
In words, this says:
Find the log to the base +e+ of this expression:
e^( a certain log )
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The expression simply refers to the log, so
+ln%28+e%5E%28-.4%29+%29+=+-.4+