SOLUTION: How do I graph {{{y=3 Ln x-2}}} I know the vertical asymptote is x=-2 but I have no idea how to graph this. Can you please show me the steps to graphing this?
Question 951213: How do I graph I know the vertical asymptote is x=-2 but I have no idea how to graph this. Can you please show me the steps to graphing this? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! How do I graph y=3+Ln+x-2 I know the vertical asymptote is x=-2 but I have no idea how to graph this. Can you please show me the steps to graphing this?
***
I think you meant to write the equation as y=3+ln(x-2)
Assuming this is the right equation you want to graph, here are the steps to take:
First, graph the basic lnx curve, which like all log curves, have an x-intercept at 1. (log(0)=1), and a asymptote: y-axis or x=0.
Second, changing the basic curve to ln(x-2) moves the entire curve 2 units right, which places the x-intercept at 3 and the asymptote at x=2.
Finally, adding 3, raises the curve 3 units up with no change to the asymptote at x=2
(