SOLUTION: Write the expression as a sum and or difference of logarithms express powers as factors. Problem: log base 5(25x) I tried this: log base 5 25+log base 5 x so if you put it in exp

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Write the expression as a sum and or difference of logarithms express powers as factors. Problem: log base 5(25x) I tried this: log base 5 25+log base 5 x so if you put it in exp      Log On


   



Question 927994: Write the expression as a sum and or difference of logarithms express powers as factors. Problem: log base 5(25x) I tried this: log base 5 25+log base 5 x so if you put it in exponential form you get 5^x=25 and 5^x=x. I'm not sure if i'm doing this right. I get lost in the steps. The answer is supposed to be 2+log base 5 then big x.
Found 2 solutions by jim_thompson5910, MathTherapy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
log%285%2C%2825x%29%29


log%285%2C%2825%29%29%2Blog%285%2C%28x%29%29


log%285%2C%285%5E2%29%29%2Blog%285%2C%28x%29%29


2%2Alog%285%2C%285%29%29%2Blog%285%2C%28x%29%29


2%2A1%2Blog%285%2C%28x%29%29


2%2Blog%285%2C%28x%29%29


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So log%285%2C%2825x%29%29 expands out into 2%2Blog%285%2C%28x%29%29

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Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Write the expression as a sum and or difference of logarithms express powers as factors. Problem: log base 5(25x) I tried this: log base 5 25+log base 5 x so if you put it in exponential form you get 5^x=25 and 5^x=x. I'm not sure if i'm doing this right. I get lost in the steps. The answer is supposed to be 2+log base 5 then big x.

log+%285%2C+25x%29
log+%285%2C+25%29+%2B+log+%285%2C+x%29
log+%285%2C+5%5E2%29+%2B+log+%285%2C+x%29
2+%2A+log+%285%2C+5%29+%2B+log+%285%2C+x%29
2%281%29+%2B+log+%285%2C+x%29_____highlight_green%282+%2B+log+%285%2C+x%29%29