SOLUTION: how do i do this? : 1 /loga(abc) +1 /logb(abc) +1 /logc(abc) ?

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Question 785780: how do i do this? : 1 /loga(abc) +1 /logb(abc) +1 /logc(abc) ?
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
use the change of base identity:
1 /loga(abc) +1 /logb(abc) +1 /logc(abc)=
(log(a)+log(b)+log(c))/log(abc)