SOLUTION: Solve the equation: log4(x)-log4(2x-3)=3

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Question 462431: Solve the equation:
log4(x)-log4(2x-3)=3
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+log%284%2Cx%29+-+log%284%2C2x-3%29+=+3+
First, find out what +3+ is
in terms of log base 4.
+log%284%2Ck%29+=+3+
+k+=+4%5E3+
+k+=+64+
Rewrite equation as:
+log%284%2Cx%29+-+log%284%2C2x-3%29+=+log%284%2C64%29+
+log%284%2C+x%2F%282x-3%29%29+=+log%284%2C64%29+
+x%2F%282x-3%29+=+64+
+x+=+64%2A%282x+-+3%29+
+x+=+128x+-+192+
+127x+=+192+
+x+=+1.51181+
check answer:
+log%284%2C1.51181%29+-+log%284%2C2%2A1.51181+-+3%29+=+3+
+log%284%2C1.51181%29+-+log%284%2C.02362%29+=+log%284%2C64%29+
+log%284%2C1.51181%2F.02362%29+=+log%284%2C64%29+
+1.51181%2F.02362+=+64+
+1.51181+=+1.51168+
OK
I think error is due to rounding off