Question 459926: What are the steps to simplify this problem?
logc20c/logc50-logc5
(log in base c 20c divided by log base c 50 minus log base c 5) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! logc(20c)/logc50-logc5
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= {[logc(20)-logc(c)]/logc(50)}- logc(5)
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= {[logc(20)-1]/logc(50)} - logc(5)
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If your problem is really the following you get a different answer:
logc(20c)/[logc50-logc5]
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= [logc(20)-1]/[logc(50/5)]
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= [logc(20)-1]/[logc(10)]
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Cheers,
Stan H.
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