SOLUTION: Solve log base 2 (x)+ log base 2 (2x+1)=0

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Question 457945: Solve log base 2 (x)+ log base 2 (2x+1)=0
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C+x%29+%2B+log%282%2C+2x%2B1%29+=+0
==> log%282%2C+x%282x%2B1%29%29+=+0
==> x%282x%2B1%29+=+2%5E0
==> 2x%5E2+%2B+x+-+1+=+0
==> (2x-1)(x+1) = 0 ==> x = 1/2, -1.
Reject x = -1 (will not satisfy the original equation).
Hence the final answer is x = 1/2.