SOLUTION: I am trying to solve this logarithmic equation: In(2x+1)-1=In(x-2) I have the answer provided in the text of 8.9611, but would like to see the solution outlined. Thank you.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am trying to solve this logarithmic equation: In(2x+1)-1=In(x-2) I have the answer provided in the text of 8.9611, but would like to see the solution outlined. Thank you.      Log On


   

Question 289249: I am trying to solve this logarithmic equation: In(2x+1)-1=In(x-2) I have the answer provided in the text of 8.9611, but would like to see the solution outlined. Thank you.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Ln%282x%2B1%29-1=Ln%28x-2%29
Ln%282x%2B1%29-Ln%28x-2%29+=+1
Ln%28%282x%2B1%29%2F%28x-2%29%29+=+1
e%5E%28Ln%28%282x%2B1%29%2F%28x-2%29%29%29+=+e%5E1
%282x%2B1%29%2F%28x-2%29+=+2.7183
2x%2B1+=+2.7183%28x-2%29
2x+%2B+1+=+2.7183x+-+5.4366
6.4366+=+0.7183x
6.4366%2F0.7183+=+x+
8.961+=+x
Round off error in the difference in the results. Keep more significant digits and the answer will come closer to the one in your book