SOLUTION: Please help with this equation: log(base a) 5 = -3/4

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Question 267671: Please help with this equation:
log(base a) 5 = -3/4

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
log%28a%2C+%285%29%29+=+-3%2F4

Eventually we want an equation that says
a = some-number
So we need to get the "a" out of the base of the logarithm. We can so this by rewriting the equation in exponential form:
5+=+a%5E%28-3%2F4%29
Now we need to change the exponent on "a" to a 1 (because a%5E1+=+a). The quickest way to do this make clever use of the rules for exponents. I am going to raise both sides of the equation to the -4/3 power. (See what happens to see why.)
%285%29%5E%28-4%2F3%29+=+%28a%5E%28-3%2F4%29%29%5E%28-4%2F3%29
On the right side, the rule is to multiply the exponents. And what do you get when you multiply -3/4 and -4/3? Answer: 1!
5%5E%28-4%2F3%29+=+a
This may be an acceptable answer. If you want a decimal approximation you can use your calculator on the expression on the left side. Or, for an exact answer with rational denominators...
5%5E%28-4%2F3%29+=+a
1%2F5%5E%284%2F3%29+=+a
1%2Froot%283%2C+5%5E4%29+=+a
%281%2Froot%283%2C+5%5E4%29%29%28root%283%2C+5%5E2%29%2Froot%283%2C+5%5E2%29%29+=+a
root%283%2C+5%5E2%29%2Froot%283%2C+5%5E6%29+=+a
root%283%2C+5%5E2%29%2F5%5E2+=+a
root%283%2C+25%29%2F25+=+a