SOLUTION: log[x]=log(x+1)+1

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Question 255524: log[x]=log(x+1)+1
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
log%28x%29+=+log%28%28x%2B1%29%29+%2B+1
The problem here is that we have two logarithms. Our first step is too subtract log(x+1) from both sides.
log%28x%29+-+log%28%28x%2B1%29%29+=+1
Now, using one of the laws of logarithms (log(a) - log(b) = log(a/b)) we have:
log%28x%2F%28x%2B1%29%29+=+1
Now we rewrite the problem in exponential form as:
10%5E1+=+x%2F%28x%2B1%29
Now multiply both sides by x+1 :
10%28x%2B1%29+=+x
10x%2B10+=+x
9x+%2B+10+=+0
9x+=+-10
x+=+-10%2F9
However, you cannot take the log of a negative number. Thus, this equation has no solution.