SOLUTION: evaluate the expression 2^(log2^3)

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Question 169553: evaluate the expression
2^(log2^3)
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
evaluate the expression
2^(log2^3)
------------
=2^(log8)
= 2^0.90309...
= apx 1.870067

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that the expression is 2%5E%28log%282%2C%283%29%29%29 right??


Let y=log%282%2C%283%29%29


So 2%5E%28log%282%2C%283%29%29%29 can be rewritten as 2%5Ey.


y=log%282%2C%283%29%29 Start with the previous equation


2%5Ey=3 Rewrite the equation using the property: log%28b%2C%28x%29%29=y ====> b%5Ey=x


Since 2%5Ey=3, this means that 2%5E%28log%282%2C%283%29%29%29=2%5Ey=3 or simply 2%5E%28log%282%2C%283%29%29%29=3


So the answer is 2%5E%28log%282%2C%283%29%29%29=3