SOLUTION: Please help me solve this.
Solve for y in terms of x:log2x+log2y=1
This is all i have so far: log2xy=1 and log2 rewrites as b^p=n
So, b=2 p=1 and n=xy
What do i do afte
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-> SOLUTION: Please help me solve this.
Solve for y in terms of x:log2x+log2y=1
This is all i have so far: log2xy=1 and log2 rewrites as b^p=n
So, b=2 p=1 and n=xy
What do i do afte
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Question 140574: Please help me solve this.
Solve for y in terms of x:log2x+log2y=1
This is all i have so far: log2xy=1 and log2 rewrites as b^p=n
So, b=2 p=1 and n=xy
What do i do after this? Answer by oscargut(2103) (Show Source):
