Question 1063938: log(3xto the power of 2+8)equals to 1+log(x\2+1)
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! log(3xto the power of 2+8)equals to 1+log(x\2+1)
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log(3x^2 + 8) = 1 + log((x/2)+1)
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log[(3x^2 + 8)/((x/2)+1)] = 1
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(3x^2 + 8)/(x+2)/2 = 10
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(3x^2+8) = 5x+10
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3x^2 - 5x - 2 = 0
(3x+1)(x-2) = 0
x = (1/3) or x = 2
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Cheers,
Stan H.
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