SOLUTION: 8/3p+5/4p+9/2p
1/x+3-1/x/1/x
2x^2+2=5x
x^2-4x-1=0
x^2-3x-4is greater than or equal to 0
the absolute value of x+3 = absolute value of 2x
y=3/2x-4
y=-2x+1
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-> SOLUTION: 8/3p+5/4p+9/2p
1/x+3-1/x/1/x
2x^2+2=5x
x^2-4x-1=0
x^2-3x-4is greater than or equal to 0
the absolute value of x+3 = absolute value of 2x
y=3/2x-4
y=-2x+1
Log On
Question 38250: 8/3p+5/4p+9/2p
1/x+3-1/x/1/x
2x^2+2=5x
x^2-4x-1=0
x^2-3x-4is greater than or equal to 0
the absolute value of x+3 = absolute value of 2x
y=3/2x-4
y=-2x+1 Answer by lyra(94) (Show Source):