Question 136439
{{{(y/(y-4)) -(6/(y+7))= (y^2/(y^2+3y-28))}}}<br>

First off we need to find a common denominator.  To do this I suggest factoring the denominator on the right hand side and seeing what you get. <br>

y^2+3y-28
we need factors that add to 3 but multiply to -28
28: 
1,28
2,14
-4,7<br>

-4+7 = 3 and -4(7)=-28 so we know that 
y^2+3y-28
=(y-4)(y+7)<br>

Now that the denominator is factored it is very easy to see that our common denominator is going to be (y-4)(y+7) because every rational expression has either a y-4 or a y+7 in it.  So multiply the top of the left hand side and right hand side by (y-4)(y+7) and solve the remaining equation.<br>

{{{(y/(y-4)) -(6/(y+7))= (y^2/((y-4)(y+7)))}}} --> Multiply by your common denominator.
{{{(y(y-4)(y+7)/(y-4)) -(6(y-4)(y+7)/(y+7))= (y^2(y-4)(y+7)/((y-4)(y+7)))}}} --> cancel like terms
y(y+7)-6(y-4)= y^2 --> Distribute
y^2+7y-6y+24 = y^2 --> Collect Like Terms
y^2-y^2+7y-6y+24 = 0 --> Simplify
y+24 = 0 --> Subtract 24 from both sides(solve for y)
y = -24