Question 136354
Please help me, it asks:
In the equation ax^2+bx+c=0, the value of b^2-4ac is called the discriminant of the quadratic equation. What does this value tell you about the real roots of the equation?
I solved this, and it turned out wrong. Please help me, Thank You=)
<pre><font size = 4 color = "indigo"><b>
If a, b  and c are all real numbers in {{{ax^2+bx+c=0}}}, then: 

The discriminant {{{b^2-4ac}}}, when calculated, will either turn out to be a
positive number, a negative number or zero.

If {{{b^2-4ac}}} turns out to be a positive number, there are two different
real roots.

If {{{b^2-4ac}}} turns out to be a negative number, there are NO real roots,
but there are two different conjugate imaginary (complex) roots.

If {{{b^2-4ac}}} turns out to be zero, then there is just ONE, not TWO, real
roots.

Edwin</pre>