Question 136230
Given:
{{{s(t) = -5t^2+25t}}} as the function of the height of an object propelled vertically upwards, find the velocity of the object after 1 second.
Velocity is rate of change of distance (height in this case) with respect to time, t.
To find the rate of change of the function, you would find the first derivative of s(t).
{{{d(s(t))/dt = -10t+25}}} Now substitute t = 1 second.
{{{d(s(1))/dt = -10(1)+25}}} = {{{15}}}
The velocity at 1 second is 15 m/s.