Question 136211
The sum of the measures of the interior angles of any triangle is 180 degrees.  If it is a right triangle, one of the angles has to measure 90 degrees, so the sum of the measures of the two acute angles must be 180 minus 90 = 90 degrees.  You are given that the measures of these two angles are x and 3x-10, so we can say that:


{{{x+(3x-10)=90}}}


{{{4x-10=90}}}


{{{4x=100}}}


{{{x=25}}}


Check:  One of the angles is 25, the other is 3(25)-10 = 65

25 + 65 = 90