Question 136129
SETTING UP THIS PROBREM WITH 4 PARTIAL CIRCLES.
ONE A SEMICIRCLE OF RADIUS 18 FT.
ONE QUARTER CIURCLE OF RADIUS 18 FT.
AND 2 QUARTER CIRCLES OF RADIUS 8 FT.
AREA=PI*R^2
.5*3.14*18^2=508.68 FT^2
.25*3.14*18^2=254.34 FT^2
2*.25*3.14*8^2=100.48 FT^2
TOTAL AREA IS:
508.68+254.34+100.48=863.5 FT^2 ANSWER.