Question 136151
THE MAXIMUM AREA FOR A 3 SIDED FENCE HAS A RATIO OF 1:2:1.
THE SUM OF THESE RATIOS=4.
THUS WE DIVIDE THE LENGTH OF THE FENCING 40/4=10.
THUS THE SIDES ARE 10:20:10.
PROOF:
10*20=200 YD^2 ANSWER.
9*22=198 YD^2 
11*18=198 YD^2.