Question 136133
If the probability of A occurring is x%, then the probability of "not A" is 100-x%. 

If the probability of A is 'x out of y', the probability of 'not A', is '(y-x) out of y. 

The net result is the sum of the two probabilities must be one (or 100%)

Bayes Theorem states:
P(A and B) = P(B)* P(A|B) = P(A)*P(B|A)

You are given P(A) and P(B|A) - you can do the math :-D