Question 135988
Please help with this question.  Determine the area of the triangle to the nearest tenth. Use A=bh/2.   It is a right triangle 30-60-90  and the base measure is 6squareroot3.  The height is not given.  

Area = base times height divided by 2

It's a 30-60-90 triangle.

In this type of triangle, 30 degrees is opposite a, 90 degrees is opposite 2a and 60 degrees is opposite a times the square root 3, which is written a(sqrt{3}). The value of a here is the number 6 in front of square root 3 in the given base.

The base is 6(sqrt{3}), which tells me the value of a is 6.

Since 30 degrees is opposite the height of the triangle and a = 6, then the height is 6.

A = [6(sqrt{3}) times 6]/2

A = 36(sqrt{3})/2

A = 18(sqrt{3})

Is this clear?