Question 20702
so, what appears in all 3 terms of  {{{8x^6-32x^5+4x^4}}}?


How about if i write it as {{{(4*2*x*x*x*x*x*x) - (4*8*x*x*x*x*x) + (4*1*x*x*x*x)}}}?


well, the number 4 does
and the x-terms {{{x*x*x*x}}}


So, we can take these out of all 3 terms, leaving the rest, as: {{{(4*x*x*x*x)(2*x*x - 8*x + 1)}}}


So, this is then really written as {{{(4x^4)(2x^2-8x+1)}}}. This is your answer. Try to visual the question in the "long-version" if that helps you.


jon.