Question 135764
{{{(y+3)(y-4) = -2}}}
{{{y^2 + 3y - 4y - 12 = -2}}}
{{{y^2 - y - 12 = -2}}}
{{{y^2 - y - 10 = 0}}}
You can solve using complete the square method
{{{y^2 - y = 10}}}
{{{y^2 - y + (1/2)^2 = 10 + (1/2)^2}}}
{{{(y - (1/2))^2 = 40/4 + 1/4}}}
{{{(y - (1/2))^2 = 41/4}}}
take square root of both sides
{{{y - (1/2) = (0 +-sqrt(41)) / 2}}}}
{{{y = (1 + sqrt(41))/2}}}
{{{y = (1 - sqrt(41))/2}}}
check answers
{{{(y+3)(y-4) = -2}}}
{{{((1 + sqrt(41))/2 + 3)((1 + sqrt(41))/2 - 4) = -2}}}
Multiply both sides by {{{4}}}
{{{(1 + sqrt(41) + 6)(1 + sqrt(41) - 8) = -8}}}
{{{(7 + sqrt(41))(-7 + sqrt(41)) = -8}}}
{{{-49 + 41 = -8}}}
{{{-8 = -8}}}
OK