Question 135764
(y+3)(y-4)=-2
y^2-y-12 = -2
y^2-y-10=0
y = [1 +- sqrt(1-4*-10)]/2
y = [1 +- sqrt(41)]/2
y = [1+sqrt(41)]/2 or y = [1-sqrt(41)]/2
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Cheers,
Stan H.