Question 135680
Given: {{{P=2000e^0.05t and species B, P=5000e^0.02t}}} t=0 in 2000

When do they equal??

{{{2000e^0.05t = 5000e^0.02t}}}
{{{e^0.05t = 2.5e^0.02t}}}
{{{ln(e^0.05t) = ln(2.5e^0.02t)}}}
{{{ln(e^0.05t) = ln(2.5) + ln(e^0.02t)}}}
{{{0.05t = 0.916 + 0.02t}}}
{{{0.03t = 0.916}}}
{{{t = 30.54}}} = June in the year 2030

Check your answer. Is {{{2000e^(0.05*30.54) = 5000e^(0.02*30.54)}}} ???