Question 135618
The first thing you need to do is simplify both the numerator and the denominator by finding and applying the lowest common denominator in each.


{{{(3+1/(3b))/(2-1/(6b))=((9b+1)/(3b))/((12b-1)/(6b))}}}


Now you can multiply the numerator by the inverse (By the way that is more properly termed the multiplicative inverse or reciprocal to avoid confusion with the additive inverse)


{{{((9b+1)/(3b))(6b/(12b-1))}}}


You should be able to take it from here.  Remember to take out the common factor of 3b.