Question 135533
Given: {{{x-6y=12}}}
{{{-6y=12 - x}}}
{{{y = (12-x)/(-6)}}}
{{{y = ((-1)(12-x))/((-1)(-6)) }}}   remember(-1/-1) is just a multiply by 1
{{{y = (-12+x)/(6)}}}
{{{y = (x -12)/6 }}}